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This function takes number of FTE and annual $/FTE and determines labor cost

Usage

solvecost_labor(fte, cost, time = "day")

Arguments

fte

Number of FTEs. Can be decimal.

cost

$/year per FTE

time

Desired output units, one of c("day", "month", "year"). Defaults to "day".

Value

A numeric value for labor $/time.

Examples

laborcost <- solvecost_labor(1.5, 50000)

cost_data <- data.frame(
  fte = seq(1, 10, 1)
) %>%
  dplyr::mutate(costs = solvecost_labor(fte = fte, cost = .08))